x^2+12x=192

Solution for x^2+12x=192 equation:

x^2+12x=192

We move all terms to the left:

x^2+12x-(192)=0

a = 1; b = 12; c = -192;
Δ = b2-4ac
Δ = 122-4·1·(-192)
Δ = 912
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{912}=\sqrt{16*57}=\sqrt{16}*\sqrt{57}=4\sqrt{57}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{57}}{2*1}=\frac{-12-4\sqrt{57}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{57}}{2*1}=\frac{-12+4\sqrt{57}}{2}
$